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Find sum of array using pointers is an interactive C dry run visualizer from the Pointersarrays programs section. Study the source code, then use the execution controls to follow each step, variable update, highlighted line, and console output.
This page provides a browser-based dry run with source-code highlighting, auto-scroll, voice narration controls, and execution output for learning the program step by step.
#include <stdio.h>
int main() {
int i;
int arr[] = {10, 20, 30, 40, 50, 60, 70};
int n = sizeof(arr)/sizeof(arr[0]);
int sum = 0;
int *ptr = arr;
// Method 1: Using pointer arithmetic
for(i = 0; i < n; i++) {
sum += *(ptr + i);
}
printf("Sum (method 1): %d\n", sum);
// Method 2: Moving pointer
sum = 0;
ptr = arr;
for(i = 0; i < n; i++) {
sum += *ptr;
ptr++;
}
printf("Sum (method 2): %d\n", sum);
// Method 3: While loop with end pointer
sum = 0;
ptr = arr;
int *end = arr + n;
while(ptr < end) {
sum += *ptr++;
}
printf("Sum (method 3): %d\n", sum);
return 0;
}